Gravitational force F = G m1 m2 / r^2 between two masses. How does this force relate to orbital motion?

Study for the High School Physics Test. Study with quizzes, flashcards, and multiple choice questions, each question comes with hints and explanations. Prepare effectively for your exam!

Multiple Choice

Gravitational force F = G m1 m2 / r^2 between two masses. How does this force relate to orbital motion?

Gravity is the inward pull that provides the centripetal acceleration turning a straight-line path into a curved orbit. For a circular orbit, the needed inward acceleration is v^2/r, and gravity supplies exactly that: G M m / r^2 = m v^2 / r, which gives v^2 = GM/r. This shows how the force sets the orbital speed for a given distance: closer or stronger gravity means faster motion. Gravity never acts outward or causes the speed to grow without bound; the force continually bends the path toward the center, and in non-circular orbits the speed varies as energy and distance change, but gravity remains the central inward force that keeps the body in orbit.

Gravity is the inward pull that provides the centripetal acceleration turning a straight-line path into a curved orbit. For a circular orbit, the needed inward acceleration is v^2/r, and gravity supplies exactly that: G M m / r^2 = m v^2 / r, which gives v^2 = GM/r. This shows how the force sets the orbital speed for a given distance: closer or stronger gravity means faster motion. Gravity never acts outward or causes the speed to grow without bound; the force continually bends the path toward the center, and in non-circular orbits the speed varies as energy and distance change, but gravity remains the central inward force that keeps the body in orbit.

More practice questions